I'm sure this strategy has been discussed before, but thought I would offer it up for discussion anyway. My girlfriend is still learning to play craps, and I was trying to think of a good way for her to get accustomed to the game without having to constantly coach her the whole time. In the process, I realized that this strategy was most likely also one of the easiest ways to drink for ALMOST free - and in any case, cheaper than ordering drinks from a bar at a strip casino. In addition, if you can find a casino that rates odds, then this is also a way to get some minimal comp action - enough to most likely offset any losses on the game. Girlfriend: Play pass line for $10. When a point is established, back up with $10. Experienced Player: Play don't pass line for $10. When a point is established, back up with: 4 or 10: $20 5 or 9: $15 6 or 10: $12 The result of ALMOST every situation will be an exact push. Whatever one player wins, the other player loses. The net result in almost every situation will be that together you exactly break even. All along the way? You are drinking for free, besides any tips to the cocktail waitress. And the girlfriend is learning the game at no charge. Which includes, getting to shoot the dice. (Assuming it is a bar 2 table) The only costs that come with this plan occur on the unlikely chance that the shooter rolls a 2. When this happens, the girlfriend will lose her bet, and the experienced player will push. If you are playing at a $10 table, this will mean a $10 loss. The odds of that happening are 1 time for every 36 come out rolls. In your average hour at the table, this is likely to happen less than once. Even when it does occur, you are losing far far less than the cost of drinks at a strip casino. This works no differently at a bar 12 table - other than knowing which number to root against. Any thoughts?